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BIDMAS

by goatsoup


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Description

If you've played the demo before this is now the proper version.

The 'maths checker' is massively improved so the type of errors reported in the comments should be fixed.
Also, now with 20 levels and autosave after each level.



23 Comments

goatsoup
cloa513 - not sure what you mean. What does CGI stand for?
0 12 years, 7 months ago
goatsoup
You need a multiply on either side of the equals...
0 12 years, 7 months ago
ishil99
i cant get through level 5....will someone help me?
0 12 years, 7 months ago
cloa513
Wouldn't this game be easier to program and easier to play if instead of CGI you had a select box of the numbers and operators ( ,-....).
0 12 years, 7 months ago
roro80
Hi Goat,

I'm wondering how much time a game like this took ya and your programming background? Did you study programming? What languages do u know in addition to knowing how to create potential IOS games? Thanks for creating this awesome game!

0 12 years, 8 months ago
mormord
This game made me wonder, how many solutions these puzzles have apart from trivial ones (like swapping A and B in A B = C). In the meantime, why 26-5*5= 1^87 not accepted? I guess I'm not allowed to use plus as a positive sign, only for addition.
Some more games like this, and we'll be addicted to math :)

0 13 years, 1 month ago
Rob
Those are the ideas I am in general toying with. That's what I mean logic deduction. In soduku, I think you can nail down the next answer to just one possibility. For me, I was able to nail it down to two for the diabolical ones and I usually ended up giving up.
0 13 years, 2 months ago
goatsoup
Looking at the numbers available:
The 3 digit number can't end in 0 because the answer would have to end in 0. The same logic applies to 4 (end in 8) and 7 (end in 9). So it has to end in 1,2 or 3.
Thinking about the first digit, it can't be a 7 because you can't make an answer big enough (>4900). Similar logic applies to 4 (answer would have to be > 2800 and < 3500 - can't do it). So it has to start with 1,2 or 3 as well.
This gives 7 combinations of 1,2 or 3 (1?1,1?2,1?3,2?1,2?3,3?1,3?2). If you try arranging the tiles some of these can be easily eliminated - e.g. 3?2 because you can't make an answer even close to sensible.
Now I write this out I realise how hard it is - if you get past it the next few are probably easier.

0 13 years, 2 months ago
Rob
Still stomped by this one. I am getting a headache even with the help of a calculator next to me. You don't have to give me the answer but is there any logical thinking involved here that will get me to the final answer?
0 13 years, 2 months ago
goatsoup
OK, what if I tell you that it is ??? x 7 = ????.

0 13 years, 2 months ago

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